Y = - 3x + 10 3x + y = 5 substitution method

no solutions

Step-by-step explanation:

y = - 3x + 10

3x + y = 5

Substitute the first equation into the second equation

Let every instance of y in the second equation be replaced with - 3x+10

3x + (-3x+10) = 5

Combine like terms

10 = 5

This is never true so there are no solutions

(These are parallel lines with the same slope but different y intercepts)