Ask Question
18 June, 14:11

The average price of a two-bedroom apartment in the uptown area of a prominent American city during the real estate boom from 1994 to 2004 can be approximated by p (t) = 0.15e0.10t million dollars (0 ≤ t ≤ 10) where t is time in years (t = 0 represents 1994). What was the average price of a two-bedroom apartment in this uptown area in 2002, and how fast was it increasing? (Round your answers to two significant digits.) HINT [See Quick Example 3.]

+1
Answers (1)
  1. 18 June, 17:37
    0
    p (t) = 0.19e0.10t

    =>p' (t) = 0.19e0.10t (0.10*1)

    =>p' (t) = 0.019e0.10t

    t = 0 represents 1994

    for 2002, t=2002-1994 = 8

    in 2002

    average price = p (8)

    =>average price = 0.19e0.10*8

    =>average price = 0.422853 ... million

    rate of increase = p' (8)

    =>rate of increase = 0.019e0.10*8

    =>rate of increase = 0.0422853 ... million per year

    p (8) = $ 0.42 million

    p' (8) = $ 0.042 million per year
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “The average price of a two-bedroom apartment in the uptown area of a prominent American city during the real estate boom from 1994 to 2004 ...” in 📙 Mathematics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers