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4 January, 13:14

Select each term that is a factor of

4x2-8x-12

Question 2 options:

x-3

x+3

x-1

x+1

4x

4

+3
Answers (1)
  1. 4 January, 14:50
    0
    A) (x - 3)

    D) (x + 1)

    F) 4

    Step-by-step explanation:

    4x² - 8x - 12

    4 (x² - 2x - 3)

    4[x² - 3x + x - 3]

    4[x (x - 3) + (x - 3) ]

    4 (x - 3) (x + 1)
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