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2 April, 23:34
How to solve to system y=x^2-2 y=2x+1
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Kael Bush
3 April, 00:49
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the solutions are (3, 7) and (-1, - 1)
Step-by-step explanation:
Insert the " = " symbol between the two equations, obtaining:
y = x^2 - 2 = y = 2x + 1
Then x^2 - 2 = 2x + 1, or
x^2 - 2x - 3 = 0, and this can be factored into (x - 3) (x + 1) = 0.
Thus, the x values that satisfy this system are {-1, 3}.
Use y = 2x + 1 to find the corresponding y values:
y = 2 (-1) + 1 = - 1
and
y = 2 (3) + 1 = 7
Then the solutions are (3, 7) and (-1, - 1)
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