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18 July, 00:29

The length of the rectangle is fourteen more than three times the width. The perimeter of the rectangle is 204 feet. Find the dimensions of the rectangle.

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Answers (2)
  1. 18 July, 00:41
    0
    Length l = 58ft

    Width w = 22ft

    Step-by-step explanation:

    Given;

    Perimeter P = 204 ft

    Length = fourteen more than three times the width

    Let w represent the width of the rectangle;

    Length l = 3w + 14 ... 1

    Perimeter of a rectangle can be written as;

    P = 2l + 2w

    Substituting the values of l and w;

    P = 2 (3w+14) + 2w = 8w + 28

    And P = 204 ft

    8w + 28 = 204

    8w = 204-28

    8w = 176

    w = 176/8

    w = 22ft

    Since;

    l = 2w + 14

    l = 2 (22) + 14

    l = 58ft

    Length l = 58ft

    Width w = 22ft
  2. 18 July, 02:16
    0
    Length = 80 feet, Width = 22 feet

    Step-by-step explanation:

    Let's call the length 'L' and the width 'W'. Then, we can formulate the following equations:

    L = 3*W + 14

    2L + 2W = 204 - > L + W = 102

    Using the value of L from the first equation in the second equation, we have that:

    3*W + 14 + W = 102

    4*W = 88

    W = 22 feet

    From the first equation:

    L = 3*W + 14 = 66 + 14 = 80 feet.
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