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12 March, 21:54

A function is shown f (x) = 5 (x-2) ^2+3 what is the minimum value of the function

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  1. 12 March, 23:06
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    + 3

    Step-by-step explanation:

    The equation of a parabola in vertex form is

    f (x) = a (x - h) ² + k

    where (h, k) are the coordinates of the vertex and a is a multiplier

    f (x) = (x - 2) ² + 3 ← is in vertex form

    with vertex = (2, 3)

    The minimum value occurs at the vertex and is the value of k

    k = 3, thus minimum value is 3
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