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1 June, 13:09

Which binomial must be subtracted from (10r-7) so that the difference of the 2 polynomials is (93r+12) ?

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  1. 1 June, 14:58
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    First binomial expression is A = (10r - 7).

    Let's assume second binomial expression is B.

    and third binomial expression is C = (93r + 12).

    According to given question, A - B = C.

    To find B, we can subtract C from A such that;

    B = A - C

    B = (10r - 7) - (93r + 12)

    Distributing negative sign and removing parentheses;

    B = 10r - 7 - 93r - 12

    Combining like terms;

    B = (10r - 93r) + (-7 - 12)

    B = (-83r) + (-19)

    B = - 83r - 19

    Hence, second binomial expression would be B = (-83r - 19).
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