Can you factor 2x^2+3x+12

2 (x - x1) (x - x2)

Step-by-step explanation:

y = 2x^2 + 3x - 12

Factored form of y:

y = a (x - x1) (x - x2)

Find x1 and x2, the 2 real roots of y. Use the improved quadratic formula.

D = d 2 = b 2 - 4 a c = 9 + 96 = 105 - -> d = ± √ 105 x = - b 2 a ± d 2 a = - 3 4 ± √ 105 4 Therefor, y = 2 (x + 3 4 + √ 105 4) (x + 3 4 - √ 105 4)