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12 July, 05:00

Find the value of k such that the system of equations does not have a solution:

10x+4y=-3

-15x+ky=14

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Answers (1)
  1. 12 July, 08:01
    0
    k = - 6.

    Step-by-step explanation:

    We need to make the left side of the second equation a multiple of the left side of the first one.

    We can do this by making k = - 6 (because - 15/10 = - 6/4).

    The second equation becomes

    -15x - 6y = 14

    Now multiply this by - 2/3. We get

    10x + 4y = - 28/3

    but the first equation is 10x + 4y = - 3.

    So there are no solutions.

    So the answer is k = - 6.

    ,
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