In a triangle the first angle is 10 degrees more than the second angle. The third angle is equal to the sum of first 2 angles. Find the value of all three angles

First angle = x+10

Second angle = x

Third angle = x+x+10 or 2x+10

X+10+x+2x + 10=180

4x+20=180

Subtract 20 from both sides

4x=160

Divide both sides by 4

X=40

First angle = 50

Second angle=40

Third angle = 90