What is the value of b in the equation (y^-9) ^b=y^45?

b = (log (y^45)) / log (1/y^9) + (2 i π n) / log (1/y^9) for n element Z

Step-by-step explanation:

Solve for b:

(1/y^9) ^b = y^45

Take the logarithm base 1/y^9 of both sides:

Answer: b = (log (y^45)) / log (1/y^9) + (2 i π n) / log (1/y^9) for n element Z