Y = - 3x+4 and y = 1/2x-3

{x = 2, y = - 2

Step-by-step explanation:

Solve the following system:

{y = 4 - 3 x | (equation 1)

{y = x/2 - 3 | (equation 2)

Express the system in standard form:

{3 x + y = 4 | (equation 1)

{-x/2 + y = - 3 | (equation 2)

Add 1/6 * (equation 1) to equation 2:

{3 x + y = 4 | (equation 1)

{0 x + (7 y) / 6 = (-7) / 3 | (equation 2)

Multiply equation 2 by 6/7:

{3 x + y = 4 | (equation 1)

{0 x+y = - 2 | (equation 2)

Subtract equation 2 from equation 1:

{3 x+0 y = 6 | (equation 1)

{0 x+y = - 2 | (equation 2)

Divide equation 1 by 3:

{x+0 y = 2 | (equation 1)

{0 x+y = - 2 | (equation 2)

Collect results:

Answer: {x = 2, y = - 2