The perimeter of a rectangle is 18 feet, and the area of the rectangle is 20 square feet. What is the width of the rectangle?

The width can be 5 ft or the width can be 4 ft

Step-by-step explanation:

Perimeter = 2 (l+w) for a rectangle

Area = l*w for a rectangle

Using perimeter

18 = 2 (l+w)

Divide by 2

18/2 = 2/2 (l+w)

9 = l+w

Solving for l

9-w = l

Using area

20 = l*w

Substituing for l

20 = (9-w) * w

20 = 9w - w^2

Subtract 20 from each side

20-20 = -w^2 + 9w - 20

0 = - w^2 + 9w - 20

Multiply by - 1

0 = w^2 - 9w+20

Factor

0 = (w-5) (w-4)

Using the zero product property

w-5 = 0 w-4 = 0

w = 5 w=4

The width can be 5 ft or the width can be 4 ft

4 ft or 5 ft

i think thats right