What is the area of a triangle whose sides are 10 meters, 14 meters, and 20 meters long? A. 65 m2 b. 100 m2 c. 70 m2 d. 50 m2

Answer: Option A. 65 m^2

Solution:

Sides: a=10 m, b=14 m, c=20 m

Area: A=?

A=sqrt [p (p-a) (p-b) (p-c) ]

Semi-perimeter: p = (a+b+c) / 2

p = (10 m+14 m+20 m) / 2

p = (44 m) / 2

p=22 m

A=sqrt [ (22 m) (22 m-10 m) (22 m-14 m) (22 m-20 m) ]

A=sqrt [ (22 m) (12 m) (8 m) (2 m) ]

A=sqrt [ 4,224 m^4 ]

A=64.99230723 m^2

A=65 m^2

Area for a triangle is (base • height) divided by 2.