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Mathematics
Mona
26 August, 14:05
Find the zeroes of f (x) = 2x^2+32
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Giovani Joyce
26 August, 18:00
0
first step)
with the equation + -b-√b∧2-4ac/2a you can find the zeros of the equation
second step)
for b = 0, a = 2, c = 32
+ - 0-√o∧2-4 (2) (32) / 2*2 = √-256 / 4, as you can see it, it is a negative number inside the root, and this equation do not have zeros, therefore it do not have solution
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