Y^2/y-3 x y^2-y-6/y^2+1y

Question

Mathematics

Paula Owen

3 September, 05:05

Y^2/y-3 x y^2-y-6/y^2+1y

+2

Answers (1)

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Iliana Conley · Answer 1

x-2y=6

x=2y+6

x•2-4y•2=24

(2y+6) •2-4y•2=24

(2y+6) •2-8y=24

4y+12-8y=24

12-4y=24

-4y=12

y=-3

a=x+2y + (x+2y) •2 + (x+2y) •3 + (x+2y) •4

a = (2y+6) + 2y + ((2y+6) + 2y) •2 + ((2y+6) + 2y) •3 + ((2y+6) + 2y) •4

a = (2 (-3) + 6) + 2 (-3) + ((2 (-3) + 6) + 2 (-3)) •2 + ((2 (-3) + 6) + 2 (-3)) •3 + ((2 (-3) + 6) + 2 (-3)) •4

a = (-6+6) - 6 + ((-6+6) - 6) •2 + ((-6+6) - 6) •3 + ((-6+6) - 6) •4

a=0-6-6•2-6•3-6•4

a=-6-12-18-24

a=-60

OR

x-2y=6

x=2y+6

Utilizați FOIL