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23 April, 00:54

Which equation (s) have x = 2 as the solution? log2 (5x + 6) = 4 logx16 = 4 log3 (6x + 4) = 3 logx36 = 6

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  1. 23 April, 04:31
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    First two

    log2 (5x + 6) = 4

    logx16 = 4

    Step-by-step explanation:

    log2 (5x + 6) = 4

    5x + 6 = 2⁴

    5x + 6 = 16

    5x = 10

    x = 2

    logx16 = 4

    16 = x⁴

    16 = 2⁴

    x = 2

    log3 (6x + 4) = 3

    6x + 4 = 3³

    6x = 27 - 4

    6x = 23

    x = 23/6

    logx36 = 6

    36 = x²

    36 = 6²

    x = 6
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