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8 July, 23:17

find the permimter of the quadrilateral if x=2 the perimiter is in inches the perimiters are (4x2+8x) (31) (7x+30) (3x2-5x+20)

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  1. 9 July, 00:56
    0
    115

    Step-by-step explanation:

    4*2+8 (2) = 24

    31

    7 (2) + 30 = 44

    3*2-5 (2) + 20 = 6-10+20 = - 4+20 = 16

    24+31+44+16

    115
  2. 9 July, 01:43
    0
    7 (2) + 30 = 14+30 = 44

    3 (2^2) - 5 (2) + 20 = 12 - 10 + 20 = 22

    4 (2^2) + 8 (2) = 16 + 16 = 32

    P = 31 + 44 + 22 + 32 = 129

    The perimeter is 129 inches
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