The sum of 5 consecutive integers is 505. what is the third number in this sequence?

The 5 consecutive numbers are 99,100,101,102 and 103.

Therefore 101 is the third consecutive number.

Answer

101

Explanation

Let the first term of the sequence to be a.

1st term = a

2nd term = a+1

3rd term = a+2

4th term = a+3

5th term = a+4

a + (a+1) + (a+2) + (a+3) + (a+4) = 505

5a+10=505

5a=505-10

5a=495

a=99

3rd term = a+2

=99+2

= 101