What are the dimensions of a rectangle with an area of 304 and a perimeter of 70?

Area = 304 cm^2

perimeter = 70

perimeter = 2 (l+w)

70 = 2 (l+w)

70/2 = l+w

35 = l+w

Now suppose the length would be = x

width would be = 35-x

NOW Area = l*w

304 = x * (35-x)

304 = 35x - x^2

x^2-35x+304 = 0

use quadratic formula to solve next ok