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Yesterday, 03:33

Two identical twins can only be distinguished by the characteristic that one always tells the truth and the other always lies. One twin tells you of a lucky number pair: "When I multiply my first lucky number by 3 and my second lucky number by 6, the addition of the resulting numbers produce a sum of 12. When I add my first lucky number and twice my second lucky number, the sum is 5." Which twin is talking? How do you know?

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Answers (2)
  1. Yesterday, 04:46
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    The first twin. The lucky numbers must be 2 and 1, respectively. The second twin is lying because 2 + (1x2) = 4 not 5.
  2. Yesterday, 07:01
    0
    They are the liar. If 3x + 6y = 12, then x = 2 and y = 1. If x + 2y, then 2 + 2 would equal 4, not 5.
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