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25 May, 17:01

A square with a side length of x+6 has the same perimeter as an equilateral triangle with a side length of 4 x what is the area of the square

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  1. 25 May, 20:44
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    The perimeter of the equilateral triangle is 3s and s=4x so the perimeter is:

    12x

    And we are told that the perimeter of the square is the same. And that perimeter is 4s where s = (x+6) so that perimeter is equal to

    4x+24, and again, we are told that these two values are equal so we can solve for x ...

    12x=4x+24

    8x=24

    x=3 and if x=3 then the side length is (x+6) = 9

    So the area of the square is always A=s^2 and s=9 thus:

    A=9^2

    A=81 u^2
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