The vertex form of h (x) = x2 - 14x + 6 is h (x) =

To be able to write the equation into the vertex form, it is important that we know what is the general form of this. For a quadratic equation, the vertex form is:

y = a (x - h) + k

where h and k are the vertex of the parabola.

h (x) = x^2 - 14x + 6

h (x) = (x^2 - 14x) + 6

h (x) = (x^2 - 14x + 49) + 6

h (x) = (x - 7) ^2 + 6