How do I solve 4x + 3y=0 & 2x + y = - 2 using substitution

4x + 3y = 0

2x + y = - 2

take 2x and subtract to the side with - 2

it'll look like this: y = - 2x - 2

plug that equation in where the y is in the other equation.

it'll look like this: 4x + 3 (-2x - 2) = 0

which you multiply 3 and the - 2x and the - 2

which the equation would be: 4x - 6x - 6=0

put together like terms: - 2x - 6=0

add the 6 to the side with the zero: - 2x = 6

divide both sides by - 2 which x = - 3

to get y you plug in the answer for x (-3)

2 (-3) + y = - 2

so it'd then be - 6 + y = - 2

add the - 6 to the side with - 2

y = - 2 + 6

y = 4

so your complete answer is (-3, 4)