Approximate the real number solution (s) to the polynomial function f (x) = x3 + 2x2 - 5x - 6.

a. x = - 3, x = - 1, x = 2

b. x = 3, x = 1, x = - 2

c. x = 3, x = - 1, x = 2

d. x = - 3, x = 1, x = - 2

F (1) = (1) ^3 + 2 (1) ^2 - 5 (1) - 6 = 1 + 2 - 5 - 6 = - 8; x = 1 is not a solution to the polynomial.

f (-1) = (-1) ^3 + 2 (-1) ^2 - 5 (-1) - 6 = - 1 + 2 + 5 - 6 = 0; x = - 1 is a solution to polynomial.

From the options, a or c has x = - 1, both has x =, so lets check for x = 3

f (3) = (3) ^3 + 2 (3) ^2 - 5 (3) - 6 = 27 + 18 - 15 - 6 = 24; x = 3 is not a solution to the polynomial.

Therefore the solutions to the polynomial are x = - 3, x = - 1, x = 2