Ask Question
22 September, 14:48

Solve using integrating factor (x^5+3y) dx-xdy=0

tnx

+5
Answers (1)
  1. 22 September, 18:47
    0
    (x^5 + 3y) dx - xdy = 0

    x^5 + 3y - xdy/dx = 0

    3y - xdy/dx = - x^5

    dy/dx - 3/x y = x^4

    I. F. = e^∫ (-3/x) = 1/x^3

    (dy/dx) / x^3 - (3/x) y/x^3 = x^4/x^3

    (dy/dx) / x^3 - 3/x^4 y = x

    (1/x^3 y) ' = x

    ∫ (1/x^3 y) 'dx = xdx

    1/x^3 y = 1/2 x^2 + c

    y = (x^5) / 2 + cx^3
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “Solve using integrating factor (x^5+3y) dx-xdy=0 tnx ...” in 📙 Mathematics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers