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MathematicsMathematics
26 January, 01:22

A company produces individually wrapped spherical biscuits. The minimum amount of wrapping material needed to cover a biscuit, assuming no edges overlap, is 200.96 square centimeters. What is the diameter of one biscuit?

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  1. 26 January, 03:34
    0
    The surface area of the spherical biscuit is calculated through the equation,

    A = 4πr²

    We are given with one surface area, that is the amount of wrapper per biscuit.

    200.96 = 4πr²

    The value of r from the equation is 5.65 cm. A diameter is twice the value of the radius. Thus, the answer is 11.3 centimeters.
  2. 26 January, 04:22
    0
    The answer is 8 cm.

    Just took the test on edenguity.

    Yuh Welcome.
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Home » Mathematics » A company produces individually wrapped spherical biscuits. The minimum amount of wrapping material needed to cover a biscuit, assuming no edges overlap, is 200.96 square centimeters. What is the diameter of one biscuit?
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