A company produces individually wrapped spherical biscuits. The minimum amount of wrapping material needed to cover a biscuit, assuming no edges overlap, is 200.96 square centimeters. What is the diameter of one biscuit?

Question

Mathematics

Jefferson

26 January, 01:22

A company produces individually wrapped spherical biscuits. The minimum amount of wrapping material needed to cover a biscuit, assuming no edges overlap, is 200.96 square centimeters. What is the diameter of one biscuit?

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Answers (2)

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Orion · Answer 1

The surface area of the spherical biscuit is calculated through the equation,

A = 4πr²

We are given with one surface area, that is the amount of wrapper per biscuit.

200.96 = 4πr²

The value of r from the equation is 5.65 cm. A diameter is twice the value of the radius. Thus, the answer is 11.3 centimeters.

Urijah Rowe · Answer 2

The answer is 8 cm.

Just took the test on edenguity.

Yuh Welcome.