Solve x2 + 20x + 100 = 36 for x.

a. x = - 16 or x = - 4

b. x = - 10

c. x = - 8

d. x = 4 or x = 16

Question

Mathematics

Saniyah Mejia

15 September, 09:44

Solve x2 + 20x + 100 = 36 for x.

a. x = - 16 or x = - 4

b. x = - 10

c. x = - 8

d. x = 4 or x = 16

+1

Answers (1)

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Ramiro Baxter · Answer 1

X² + 20x + 100 = 36⇒ x² + 20x + 100 - 36 = 0⇒ x² + 20x + 64 = 0

Δ = b²-4ac = 20² - 4·1·64 = 400-256 = 144

x₁ = (-b+√Δ) / 2a = (-20+√144) / 2·1 = (-20+12) / 2 = - 8/2 = - 4

x₂ = (-b-√Δ) / 2a = (-20-√144) / 2·1 = (-20-12) / 2 = - 32/2 = - 16

x=-4 or x=-16

Solve x2 + 20x + 100 = 36 for x.a. x = - 16 or x = - 4b. x = - 10c. x = - 8d. x = 4 or x = 16

Solve x2 + 20x + 100 = 36 for x.

a. x = - 16 or x = - 4

b. x = - 10

c. x = - 8

d. x = 4 or x = 16