What is the y value of the vertex?

y=x^2-10x+24

Hack way

find x value then plug back

to find the x value of the vertex in form

y=ax^2+bx+c

the x value is - b / (2a)

so

y=1x^2-10x+24

x value is - 10 / (2*1) = - 10/2=5

sub back

y=5^2-10 (5) + 24

y=25-50+24

y=25+24

y=49

y value is 49

x from - 6 to 25, y from - 50 to 10, x^2 - 10x - 24

vertex = (5,-49)

x intercept=-2 & 12

y intercept=-24