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20 November, 20:02

Given the functions a (x) = 3x - 12 and b (x) = x - 9, solve a[b (x) ].

A. a[b (x) ] = 3x2 - 21

B. a[b (x) ] = 3x2 - 39

C. a[b (x) ] = 3x - 21

D. a[b (x) ] = 3x - 39

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  1. 20 November, 21:49
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    A (x) = 3x - 12

    b (x) = x - 9

    a (b (x)) = a (x - 9) = 3 (x - 9) - 12 = 3x - 27 - 12 = 3x - 39

    a (b (x)) = 3x - 39
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