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Yesterday, 22:26

If f (x) = x^2-x+1 and g (x) = 2x-1 then what is g (f (3))

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  1. Yesterday, 23:00
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    Hello,

    f (x) = x²-x+1

    g (x) = 2x-1

    g (f (x)) = g (x²-x+1) = 2 (x²-x+1) - 1=2x²-2x+1

    g (f (3)) = 2*3²-2*3+1=18-6+1=13
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