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Mathematics
Edgar Odonnell
Yesterday, 21:14
Derivative of sin11xcos11x
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Karter Gross
Yesterday, 22:23
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Hello here is a solution:
f' (x) = (sin11x) 'cos11x + sin11x (cos11x) '
(sin (ax+b)) '=a cos (ax+b)
(cos (ax+b)) '=-a sin (ax+b)
f' (x) = 11 cos11xcos11x-11sin11xsin11x
f' (x) = 11 (cos11x) ²-11 (sin11x) ²
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