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Trevin Barajas
8 November, 21:01
What is x2+7x+12=0 in standard form
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Gunner Tyler
8 November, 22:15
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X² + 7x + 12 = 0
x = - (7) + / - √ ((7) ² - 4 (1) (12))
2 (1)
x = - 7 + / - √ (49 - 48)
2
x = - 7 + / - √ (1)
2
x = - 7 + / - 1
2
x = - 7 + 1 x = - 7 - 1
2 2
x = - 6 x = - 8
2 2
x = - 3 x = - 4
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Micah Thornton
9 November, 01:00
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Not sure what standard form is, but I can solve for x
so I'm assuming that x2 means x squared or x^2 so
x^2+7x+12=0
since it equals zero, if we can factor it, then
if we have xy=0 then x and/or y=0 so
to factor x^2+7x+12
find what 2 numbers multiply to get 12 and add to get 7 so
12=2 times 2 times 3 or 2 times 6 or 1 times 12 or 3 times 4
the numbesr are 4 times 3 so
x^2+7x+12
facotrs out to
(x+4) (x+3) so
x^2+7x+12=0
(x+4) (x+3) = 0
set each to zero
x+4=0 and x+3=0
x+4=0
subtract 4 form both sides
x=-4
x+3=0
subtract 3 from both sides
x=-3
x=-4 or - 3
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