A school is building a rectangular soccer field that has an area of 6000 yards. The soccer field must be 40 yards longer than it's worth. Determine algebraically the dimensions of the soccer field, in yards. Show / explain work

Given, soccer field length is 40 m longer than width

lets consider width=w

so, length = w+40

area = length*width=6000

(w+40) * w=6000

w^2 + 40*w-6000=0;

w^2 + (100*w-60*w) - 6000=0

(w^2 + 100*w) - (60*w+6000) = 0

w (w+100) - 60 (w+100) = 0

(w+100) (w-60) = 0

w=60, because width will not be '-100'

w=60 and L=60+40=100