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1 January, 14:02

Suppose the heights of men are normally distributed with mean, μ = 69.5 inches, and standard deviation, σ = 4 inches. suppose admission to a summer basketball camp requires that a camp participant must be in the top 40 % of men's heights, what is the minimum height that a camp participant can have in order to meet the camp's height admission requirement?

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  1. 1 January, 16:52
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    To evaluate for the height we use the z-score formula given by:

    z = (x-mu) / sig

    where:

    mean=mu=69.5 inches

    sig=standard deviation=4

    Given that:

    P (x>X) = 0.40

    then

    P (x
    thus the z-value corresponding to this is:

    P (z
    hence:

    0.25 = (x-69.5) / 4

    solving for x we get:

    1=x-69.5

    x=1+69.5

    x=70.5

    thus the minimum height should be 70.5 inches
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