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23 July, 00:29

Henry invest 4500 at a compound interest rate of 5% per annum. At the end of n complete years the investment has grown to 5469.78. Find the value of n

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  1. 23 July, 04:17
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    4500 x 1.05^n = 5469.78 Solve for n

    n≈4.00001

    n=4
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