The length of a rectangle is 2 more than three times the width. The area of the rectangle is 161 square inches. What are the dimensions of the rectangle?
If x = the width of the rectangle, which of the following equations is used in the process of solving this problem?
2x^2 + 3x - 161 = 0
3x^2 + 2x - 161 = 0
6x^2 - 161 = 0
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