Ask Question
25 January, 15:31

Find the number of real number solutions for the equation.

X^2-10x+25=0

A: 2

B: Cannot be determined

C: 0

D: 1

+3
Answers (2)
  1. 25 January, 16:34
    0
    Determinant = b² - 4ac = (-10) ² + 4*1*25 = 100 - 100 = 0

    So it has 1 solution.

    Answer is D
  2. 25 January, 18:35
    0
    Hello here is a solution:

    x²-10x+25 = 0

    x² - 2 (x) (5) + 5² = 0

    puy identity : a²-2ab+b² = (a-b) ²

    (x-5) ² = 0

    x-5 = 0

    the solution is : 5
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “Find the number of real number solutions for the equation. X^2-10x+25=0 A: 2 B: Cannot be determined C: 0 D: 1 ...” in 📙 Mathematics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers