Solve the equation (3x+2) (x-4) = 0 enter the solution with the highest value.

Using completing the square:

(3x+2) (x-4) = 0

3x^2 - 12x + 2x - 8 = 0

3x^2 - 10x = 8

3 (x^2 - 10x/3) = 8

3 ((x - 10/6) ^2 - (10/6) ^2) = 8

3 ((x - 5/3) ^2 - (5/3) ^2) = 8

3 ((x - 5/3) ^2 - 25/9) = 8

3 (x - 5/3) ^2 - 25/3 = 8

3 (x - 5/3) ^2 = 49/3

(x - 5/3) ^2 = 49/9

x - 5/3 = ±√ (49/9)

x - 5/3 = ± (7/3)

x = (5/3) ± (7/3)

x = 12/3, - 2/3

x = max (12/3, - 2/3) = 12/3

x = 4