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29 December, 02:17

One of the games in a fundraiser involves rolling a six-sided die. The rule is that a player has to donate six times the value shown on the die. What is the expected value of a donation?

A) 21

B) 27

C) 30

D) 36

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Answers (2)
  1. 29 December, 05:00
    0
    It's A.

    (6*1) + (6*2) + (6*3) + (6*4) + (6*5) + (6*6) = 126

    216/6=21
  2. 29 December, 05:00
    0
    its not 30 because its just not
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