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14 January, 22:13

Bag has five red marbles, six blue marbles, and four black marbles. What is the probability of picking a red marble, replacing it, and then picking another red marble?

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Answers (2)
  1. 14 January, 22:25
    0
    Add all the marbles together

    5 (red) + 6 (blue) + 4 (black) = 15 marbles total

    5 / 15 = 1/3

    33% chance of picking a red marble

    If you replace the red marble with another red marble, it would still be 33% since you're basically just putting the red marble back to re pick it (consecutively).

    If you replaced the red marble, it would be 4 / 15 since 5 - 1 = 4

    4 / 15 =.27

    27% of picking a red marble after replacing with a different color
  2. 14 January, 23:50
    0
    Total marbles in the bag = 15

    Red marbles in the bag = 5

    Probability of picking a red marble the first time = 5/15.

    If you put it back, then everything goes back to the beginning.

    Probability of picking a red marble the second time = 5/15.

    If you put it back, then everything goes back to the beginning.

    Probability of picking a red marble the third time = 5/15.

    If you put it back, then everything goes back to the beginning.

    Probability of picking a red marble the fourth time = 5/15.

    If you put it back, then everything goes back to the beginning.

    .

    .

    .

    Probability of picking a red marble the 20th time = 5/15.

    If you put it back, then everything goes back to the beginning.

    .

    .

    .

    Probability of picking a red marble the ' Nth ' time = 5/15.

    If you put it back, then everything goes back to the beginning.

    Probability of picking a red marble ' N ' times in a row = (5/15) ^N.

    Probability of picking a red marble 3 times in a row = (5/15) (5/15) (5/15).

    Probability of picking a red marble 2 times in a row = (5/15) x (5/15)

    = (25/225) = 1/9

    = 11.1% (rounded).
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