How do I show work for 5 - (a-4) = 3 (a+2)

5 - (a-4) = 3 + (a+2)

distribute invible - 1

5-a+4=4+a+1

9-a=a+5

add a to both sides

9=2a+5

minus 5 both sides

4=2a

divide by 2 both sides

2=a

Here is how I would show the work for this problem

5 - (a-4) = 3 (a+2)

5-a+4 = 3*a+3*2

5-a+4 = 3a+6

-a+9 = 3a+6

-a+9+a = 3a+6+a

9 = 4a+6

9-6 = 4a+6-6

3 = 4a

4a = 3

4a/4 = 3/4

a = 3/4

So the solution is the fraction a = 3/4 (in decimal form 0.75)

Let me know if you have any questions or issues with any of the steps shown above. It's a lot to take in so feel free to ask about anything really.