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Find all complex solutions of 2x^2+3x+5=0 using the quadratic equation.

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  1. Today, 02:38
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    2x^2 + 3x + 5 = 0

    a = 2 b = 3 and c = 5

    x = [-b + - sq root (b^2 - 4ac) ] / 2a

    x = [-3 + - sq root (9 - 4*2*5) ] / 4

    x = [-3 + - sq root (9 - 40) ] / 4

    x = - (3 / 4) + sq root (-36) / 4

    x = - (3 / 4) - sq root (-36) / 4
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