Admission to the zoo is $6 for children and $9 for adults. On a certain day, 1480 people go to the zoo and $10,500 is collected.

How many children and adults went to the zoo?

6x+9y = 10500

x+y = 1480

Using elimination I get: 6x + 9y = 10500 - 6x-6y = - 8880

Add the 2 equations and I get 3y = 1620

Divide both sides by 3 and I get y = 540

Substitute that back in to 6x+9y = 10500.

I get that 6x+9*540 = 10500 9 * 540 = 4860

Subtract 4860 from both sides and I get 6x = 5640

Divide both sides by 6 and I get x = 940

So there must have be 940 children and 540 adults