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14 December, 09:53

Find the axis of symmetry for this parabola y=-5x^2-10x-15 write it as an equation

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Answers (2)
  1. 14 December, 11:48
    0
    Axis of symmetry is the x value of the vertex

    the x value of the vertex, in form

    y=ax^2+bx+c is - b / (2a)

    so

    y=-5x^2-10x-15

    a=-5

    b=-10

    x value of vertex is - (-10) / (2*-5) = 10/-10=-1

    x=-1 is axis of symmetry
  2. 14 December, 12:16
    0
    X = - 1

    Is this what you were looking for?
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