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6 July, 14:30

What is the third term in the expansion of the binomial (2x 5) 5?

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  1. 6 July, 16:42
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    Hello,

    1

    1 1

    1 2 1

    1 3 3 1

    1 4 6 4 1

    1 5 10 10 5 1

    (2x+5) ^5=1 * (2x) ^5+5 * (2x) ^4*5+10 * (2x) ^3*5^2+10 * (2x) ^2*5^3+5 * (2x) * 5^4+5^5

    Third term is 10*8*x^3*25=2000 x^3
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