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23 August, 02:18

1) Five hundred tickets were sold for a fundraising dinner. The receipts totaled $3312.50. Adult tickets were $7.50 each and children's tickets were $4.00 each. How many tickets of each type were sold? (375,125) that's the answer I need the steps

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Answers (2)
  1. 23 August, 03:06
    0
    Have the x=the number of adult tickets sold, and y=the number of child tickets sold.

    Your two equations should be:

    7.50x+4.00y=3312.50

    x+y=500

    :p
  2. 23 August, 05:05
    0
    Number of adults' tickets (x) : $7.50x + $4.00 (500 - x) = $3,312.50 $7.50x + $2,000.00 - $4.00x = $3,312.50 $3.50x = $1,312.50 x = 375

    No. of children's tickets (500 - x) : = 500 - 375 = 125

    Answer: 375 adults' tickets, 125 children's tickets

    Proof (Receipts totaled $3,312.50) : = (375 tickets * $7.50) + (125 tickets * $4.00) = $2,812.50 + $500.00 = $3,312.50
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