Factor completely: 2x^4+14x^3-88x^2

So first factor out the 2 in the whole equation

(2) (x^4+7x^3-44x^2)

factor out the x^2

(2) (x^2) (x^2+7x-44)

factor

x^2+7x-44

find what 2 numbers multiply to get - 44 and add to get 7

factor - 44

-44=-1 times 2 times 2 times 11

2 times 2=4

4 times 11=44

11-4=7

the numbers are 11 and - 4

(2) (x^2) [ (x^2+7x-44) ]

(2) (x^2) [ (x+11) (x-4) ]

the factored form is

(2) (x^2) (x+11) (x-4)

First / whole equation by 2x^2 leaving 2x^2 (x^2+7x-44) then xtreme method

/-44/

/ / 2 factors that multiply to get - 44 and then add to get 7

-11 / / 4

/ 7 / making ur final equation 2x^2 (x-11) (x+4)