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14 June, 18:47

If a lawn measures 40 and 4/5 ft by 50 and 7/8ft how many square feet of seed will he need?

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Answers (2)
  1. 14 June, 20:15
    0
    To solve this just take 40 4/5*50 7/8=2075.7 so there would be about 2075.7 square feet of seed to plant.
  2. 14 June, 21:28
    0
    So convert to improper fracitons (improper=x/y where x>y and the current one is mixed where it is in t s/f form) so

    40 and 4/5 = (40 times 5) / 5 and 4/5=200/5 and 4/5=204/5

    50 and 7/8 = (50 times 8) / 8 and 7/8=400/8 and 7/8=407/8

    area=legnth times width

    legnth = 407/8

    width=204/5

    multiply 407/8 and 204/5

    407/8 times 204/5 = (407 times 204) / (8 times 5) = 83028/40=2075.7 square feet

    the answer is 2075.7 ft^2 of seed
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