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15 June, 20:40

The function f (x) = tan (3/2x-pi/2) has:

A) period pi/3 and asymptote at x=pi/3

B) period 2pi/3 and asymptote at x=0

C) period 2pi/3 and asymptote at x=pi/3

D) period pi/3 and asymptore at x=0

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Answers (1)
  1. 15 June, 21:09
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    I think the best option here is B. period 2pi/3 and asymptote at x=0

    because period of tanx is pi so period of tan (3/2x) is pi / (3/2) = 2pi/3. I hope this can work good for you.
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